Evaluating Postfix Expression
Evaluating a postfix expression involves iterating through each symbol in the expression and performing operations based on whether the symbol is an operand or an operator. Here's a simple algorithm to evaluate a postfix expression:
Algorithm
1.Initialize an empty stack.
2.Scan the expression from left to right:
- For each symbol in the expression:If it's an operand (a number), push it onto the stack.
- Pop the required number of operands from the stack (e.g., two operands for binary operators).
- Perform the operation using the operator and operands.
- Push the result back onto the stack.
3.After scanning the entire expression, the result should be on the top of the stack. Pop it to get the final result.
Example:
Expression: 23*5+
Symbol: 2
Stack: [2]
Symbol: 3
Symbol: 3
Stack: [2, 3]
Symbol: *
Symbol: *
Pop two operands (3 and 2), perform 3 * 2, and push the result (6) back.
Stack: [6]
Symbol: 5
Stack: [6]
Symbol: 5
Stack: [6, 5]
Symbol: +
Symbol: +
Pop two operands (5 and 6), perform 5 + 6, and push the result (11) back.
Stack: [11]
At this point, the expression is fully evaluated, and the result (11) is at the top of the stack.
So, the stack content during the evaluation of 23*5+ was as follows:[2]
[2, 3]
[6]
[6, 5]
[11]
After the entire expression is processed, the final result (11) is at the top of the stack.
Example:5 2 3 - + 2/ ( University Question)
Stack: [11]
At this point, the expression is fully evaluated, and the result (11) is at the top of the stack.
So, the stack content during the evaluation of 23*5+ was as follows:[2]
[2, 3]
[6]
[6, 5]
[11]
After the entire expression is processed, the final result (11) is at the top of the stack.
Example:5 2 3 - + 2/ ( University Question)
Symbol:5
Stack: [5]
Symbol:2
Stack: [5,2]
Symbol:3
Stack: [5,2,3]
Symbol: -
Pop two operands (2 and 3), perform 2 - 3, and push the result (-1) back.
Stack: [5,-1]
Symbol:+
Pop two operands (5 and -1), perform 5 - 1, and push the result (4) back.
Stack: [4]
Symbol:2
Stack: [4,2]
Symbol:/
Pop two operands (4 and 2), perform 4/2, and push the result (2) back.
Stack: [2]
After the entire expression is processed, the final result (2) is at the top of the stack.
C Program- Evaluation of Postfix Expression
/****************************************************************************/
#include <stdio.h>
#include <ctype.h>
#define MAXSTACK 100
#define POSTFIXSIZE 100
/* declare stack and its top pointer to be used during postfix expression
evaluation*/
int stack[MAXSTACK];
int top = -1;
/* define push operation */
void push(int item)
{
if (top >= MAXSTACK - 1) {
printf("stack over flow");
return;
}
else {
top = top + 1;
stack[top] = item;
}
}
/* define pop operation */
int pop()
{
int item;
if (top < 0) {
printf("stack under flow");
}
else {
item = stack[top];
top = top - 1;
return item;
}
}
/* define function that is used to input postfix expression and to evaluate it */
void EvalPostfix(char postfix[])
{
int i;
char ch;
int val;
int A, B;
/* evaluate postfix expression */
for (i = 0; postfix[i] != '$'; i++) {
ch = postfix[i];
if (isdigit(ch)) {
/* we saw an operand,push the digit onto stack
ch - '0' is used for getting digit rather than ASCII code of digit */
push(ch - '0');
}
else if (ch == '+' || ch == '-' || ch == '*' || ch == '/') {
/* we saw an operator
* pop top element A and next-to-top elemnet B
* from stack and compute B operator A
*/
A = pop();
B = pop();
switch (ch) /* ch is an operator */
{
case '*':
val = B * A;
break;
case '/':
val = B / A;
break;
case '+':
val = B + A;
break;
case '-':
val = B - A;
break;
default:
printf("Invalid operator\n");
exit(1);
}
/* push the value obtained above onto the stack */
push(val);
}
}
printf(" \n Result of expression evaluation : %d \n", pop());
}
int main()
{
int i;
/* declare character array to store postfix expression */
char postfix[POSTFIXSIZE];
printf("ASSUMPTION: There are only four operators(*, /, +, -) in an expression and operand is single digit only.\n");
printf(" \nEnter postfix expression,\npress right parenthesis '$' for end expression : ");
/* take input of postfix expression from user */
for (i = 0; i <= POSTFIXSIZE - 1; i++) {
scanf("%c", &postfix[i]);
if (postfix[i] == '$')
{
break;
}
}
/* call function to evaluate postfix expression */
EvalPostfix(postfix);
return 0;
}
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